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Home/ Questions/Q 1036491
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:42:47+00:00 2026-05-16T14:42:47+00:00

Here is my code: def detLoser(frag, a): word = frag + a if word

  • 0

Here is my code:

def detLoser(frag, a):
    word = frag + a

    if word in wordlist:
        lost = True
    else:
        for words in wordlist:
            if words[:len(word) == word:
                return #I want this to break out.

            else:   
                lost = True

Where I have a return, I’ve tried putting in both return and break and both give me errors. Both give me the following error: SyntaxError: invalid syntax. Any Ideas? What is the best way to handle this?

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:42:48+00:00Added an answer on May 16, 2026 at 2:42 pm

    You’ve omitted the ] from the list slice. But what is the code trying to achieve, anyway?

    foo[ : len( foo ) ] == foo
    

    always!

    I assume this isn’t the complete code — if so, where is wordlist defined? (is it a list? — it’s much faster to test containment for a set.)

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