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Home/ Questions/Q 6828981
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:26:50+00:00 2026-05-26T22:26:50+00:00

Here is my code: echo ‘<table class=class1><tbody>’; while ($row1=mysql_fetch_array($result1)){ echo ‘<tr><td>’.$row1[‘firstname’].'</td><td>’.$row1[‘lastname’].'</td></tr>’; } echo ‘</tbody></table>’;

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Here is my code:

echo '<table class="class1"><tbody>';
while ($row1=mysql_fetch_array($result1)){
 echo '<tr><td>'.$row1['firstname'].'</td><td>'.$row1['lastname'].'</td></tr>';
}
echo '</tbody></table>';

When I use the HTML validator, it returns a good and a proper error “trimming empty <tbody>“. It happens in the case when there are 0 rows selected. So, the code looks like <table><tbody></tbody></table>, and that is not good.

I’m thinking of the best way to exclude this error (do not display this table at all when there are 0 rows or something like that), but I don’t know the best way how to do that.

How’s the idea to check if mysql_num_rows()>0 before choosing to display echo '<table class="class1"><tbody>'; ? Any better ideas or is this one good?

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:26:50+00:00Added an answer on May 26, 2026 at 10:26 pm

    Use mysql_num_rows($result) to check whether the query has any results. If true, create a table + rows. Otherwise, do nothing, or add an alternative block:

    if (mysql_num_rows($result) > 0) {
        echo '<table class="class1"><tbody>';
        while ($row1=mysql_fetch_array($result1)){
           echo '<tr><td>'.$row1['firstname'].'</td><td>'.$row1['lastname'].'</td></tr>';
        }
        echo '</tbody></table>';
    } else { //Optional
        echo '<!-- Anything -->';
    }
    
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