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Home/ Questions/Q 8945857
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T12:21:21+00:00 2026-06-15T12:21:21+00:00

Here is my code for creating an XML file public void CreateXml(string[] names, string[]

  • 0

Here is my code for creating an XML file

public void CreateXml(string[] names, string[] values, string type)
{
        XElement xml = new XElement("Transaction",
            new XElement("TransactionType", type));
        foreach (var i in names)
        {
            foreach (var o in values)
            {
                xml.Add(new XElement(i.Replace(" ", string.Empty), o));
            }
        }
        xml.Save("C:\\Users\\PHWS13\\Desktop\\sample.xml");
}

And my output looks like this

<?xml version="1.0" encoding="UTF-8"?>
<Transaction> 
    <TransactionType>Void</TransactionType> 
    <Zip>1</Zip>
     <Zip>2</Zip> 
     <PNRef>1</PNRef> 
     <PNRef>2</PNRef> 
 </Transaction>

But it is not right, I am expecting more like this

<?xml version="1.0" encoding="UTF-8"?>
<Transaction> 
    <TransactionType>Void</TransactionType> 
    <Zip>1</Zip>
     <PNRef>2</PNRef> 
 </Transaction>

As I have noticed the values are correct but it i just duplicates, How can I fix this?

string[] textBoxNamesArray = flowLayoutPanelText.Controls.OfType<TextBox>()
                                  .Select(r => r.Name)
                                  .ToArray();

string[] textBoxTextsArray = flowLayoutPanelText.Controls.OfType<TextBox>()
                                  .Select(r => r.Text)
                                  .ToArray();
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T12:21:22+00:00Added an answer on June 15, 2026 at 12:21 pm

    You shouldn’t use two nested loops then: two nested loops create a Cartesian product (i.e. every name is paired up with every value).

    If you use a single loop that goes through names and values at the same time, you’d get your expected output.

    If you are using .NET 4, you could use Zip method, like this:

    xml.Add(
        names
        .Zip(values, (n,v) => new XElement(n.Name(" ", string.Empty), v))
        .ToArray()
    );
    
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