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Home/ Questions/Q 846477
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T06:37:13+00:00 2026-05-15T06:37:13+00:00

here is my code function check($dt) { $date = date(Y-m-d); $start = new DateTime($date);

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here is my code

    function check($dt) {
    $date = date("Y-m-d");
    $start = new DateTime($date);
    $end   = new DateTime($dt);
    $diff  = $start->diff( $end );

    return $diff->format( '%d days' );
    }

print check('2009-12-14');

that prints 29 days

where am i wrong ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:37:13+00:00Added an answer on May 15, 2026 at 6:37 am

    It’s explained in the manual:

    <?php
    
    $january = new DateTime('2010-01-01');
    $february = new DateTime('2010-02-01');
    $interval = $february->diff($january);
    
    // %a will output the total number of days.
    echo $interval->format('%a total days')."\n";
    
    // While %d will only output the number of days not already covered by the
    // month.
    echo $interval->format('%m month, %d days');
    
    ?>
    

    You want:

    function check($dt) {
        $date = date("Y-m-d");
        $start = new DateTime($date);
        $end   = new DateTime($dt);
        $diff  = $start->diff( $end );
    
        return $diff->format( '%a days' );
    }
    
    print check('2009-12-14');
    

    gives 180 days.

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