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Home/ Questions/Q 7894093
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T07:18:20+00:00 2026-06-03T07:18:20+00:00

Here is my code: function function1() { var ids = GetIds(); // predefined function

  • 0

Here is my code:

function function1() {
    var ids = GetIds(); // predefined function
    if (ids.length === 0) {
        alert("Please select at least one item to procees.");
        return;
    }

    ...
}

function function2() {
    var ids = GetIds(); // predefined function
    if (ids.length === 0) {
        alert("Please select at least one item to procees.");
        return;
    }

    ...
}

function function3() {
    var ids = GetIds(); // predefined function
    if (ids.length === 0) {
        alert("Please select at least one item to procees.");
        return;
    }

    ...
}

How to extract the common part out? How to re-factor the code? The return statement is very hard to deal with. Is there any pattern relating to re-factor this code?

Thanks in advance!

    if (ids.length === 0) {
        alert("Please select at least one item to procees.");
        return;
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T07:18:22+00:00Added an answer on June 3, 2026 at 7:18 am

    You can’t. The only thing you can do is moving the alert() into GetIds(). However, the function name would be a bit confusing in this case.

    var ids = GetIds();
    if(!ids) return;
    

    Or you could change it like this:

    GetIds(function(ids) {
    
    });
    

    Your GetIds function would then look e.g. like this:

    function GetIds(callback) {
        var ids = ....;
        if(!ids) alert('...');
        else callback(ids);
    }
    
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