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Home/ Questions/Q 3217886
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T15:27:48+00:00 2026-05-17T15:27:48+00:00

Here is my code : function search_buddy() { $.post(num.php,function (ret){ num=ret; }); $(#Layer7).html(num); }

  • 0

Here is my code :

function search_buddy() 
{
    $.post("num.php",function (ret){
        num=ret;
    });
    $("#Layer7").html(num);
}
</script>

<div id="Layer8">
     Find a buddy : 
    <input type="text" id="search" onkeyup="search_buddy()"/>&nbsp;:
</div>

Now,when i enter one character into the text box with id=search, the function search_buddy doesn’t seem to get triggered. Whereas, if i enter two characters or more,the function works perfectly.Why is this happening ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T15:27:49+00:00Added an answer on May 17, 2026 at 3:27 pm

    Best resource on DOM events: http://www.quirksmode.org/dom/events/keys.html

    It looks like your event handler “search_buddy” fires an AJAX request, which is asynchronous. The rest of the function runs in parallel with the AJAX request, so “num” is undefined before the $.post returns.

    // num is undefined here... unless your network has 0 latency
    $("#Layer7").html(num);
    

    You need to wrap this code (pasted above) in a callback function. It appears to be parameter number 3:
    http://api.jquery.com/jQuery.post/

    Untested, but best guess:

    function search_buddy() {
        $.post("num.php", function (ret) {
            num=ret;
            $("#Layer7").html(num);
        });
    }
    

    Here are some modifications to help you understand:

    function search_buddy() {
        alert("before the $.post execution");
        $.post("num.php", function (ret) {
            num=ret;
            $("#Layer7").html(num);
            alert("$.post callback");
        });
        alert("immediately after the $.post execution");
    }
    

    Note: “alert” will halt all JavaScript processing so you will be able to see what events occur when.

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