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Home/ Questions/Q 713733
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:59:39+00:00 2026-05-14T04:59:39+00:00

Here is my code: #include <stdio.h> int main(void) { FILE *fp; unsigned int i;

  • 0

Here is my code:

#include <stdio.h>

int main(void) {

        FILE *fp;
        unsigned int i;
        char bytes[512];
        fp = fopen("myFile","r");
        for(i = 0;i <= 512;i++) {
                fread(&bytes, sizeof(bytes), 1, fp);
                printf("bytes[%d]: %x\n", i, bytes[i]);
        }
}

Here is the expected output

$ hexdump myFile
0000000 aa55 aa55 0060 0000 0a17 0000 b1a5 a2ea
0000010 0000 0000 614c 7563 616e 0000 0000 0000
0000020 0000 0000 0a68 0000 1001 421e 0000 0000
0000030 f6a0 487d ffff ffff 0040 0000 002f 0000

But here is what I see from my program

bytes[0]: 55
bytes[1]: 8
bytes[2]: ffffffc8
bytes[3]: ffffffdd
bytes[4]: 22
bytes[5]: ffffffc8
bytes[6]: ffffff91
bytes[7]: 63
bytes[8]: ffffff82

My obvious guess is that I’m either addressing something incorrectly and receiving the wrong data back or I am printing it incorrectly and viewing it the wrong way.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:59:39+00:00Added an answer on May 14, 2026 at 4:59 am

    You’re reading successive 512-byte chunks from your file each time round the loop, and printing only one byte of each chunk. You might want to read those 512 bytes in one go, then print them afterwards, like this:

    fread(&bytes, sizeof(bytes), 1, fp);
    for(i = 0;i < 512;i++) {
        printf("bytes[%d]: %x\n", i, bytes[i]);
    }
    

    (Also: some error checking wouldn’t go amiss, and as Dav points out, you should check that you really are reading the expected number of bytes from the file.)

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