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Home/ Questions/Q 8638691
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T10:48:06+00:00 2026-06-12T10:48:06+00:00

here is my code: object theater extends App { val m = readInt val

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here is my code:

object theater extends App {

    val m = readInt
    val n = readInt
    val a = readInt

    val c1 = m/a + (if(m%a == 0) 0 else 1)
    val c2 = n/a + (if(n%a == 0) 0 else 1)
    print(c1 + c2)
}

But the input format is: 3 integers in the same line. But for 3 integers in one line scala will consider that as a string. How can I read that string and get the 3 values in the 3 separated variables?

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  1. Editorial Team
    Editorial Team
    2026-06-12T10:48:07+00:00Added an answer on June 12, 2026 at 10:48 am

    You could use the following code which will read a line and use the first 3 whitespace separated tokens as the input. (Expects e.g. “1 2 3” as the input on one line)

    val Array(m,n,d) = readLine.split(" ").map(_.toInt)
    
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