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Home/ Questions/Q 9017191
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T04:12:11+00:00 2026-06-16T04:12:11+00:00

Here is my code on loading the data into the array by using a

  • 0

Here is my code on loading the data into the array by using a loop :
and i want to echo the data out in words late but i receive an error “Notice: Array to string conversion in…”

for ($i = 0 ; $i < 4 ; $i++)  { 
    $options[] = $row3= mysqli_fetch_array($result3);                
}
echo $options[0];
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  1. Editorial Team
    Editorial Team
    2026-06-16T04:12:13+00:00Added an answer on June 16, 2026 at 4:12 am

    Its all about:

    $options[] = $row3= mysqli_fetch_array($result3);                
    

    mysqli_fetch_array($result3) returns an array. So $row3 is an array and $options[] is an array. So when you do print $options[0] you are printing an array.

    User print_r($options[0]); to print the complete array.

    Also you could use:

    echo $options[0]['idoptions'], $options[0]['options'];
    
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