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Home/ Questions/Q 708957
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:26:59+00:00 2026-05-14T04:26:59+00:00

Here is my code. The complete binary tree has 2^k nodes at depth k.

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Here is my code. The complete binary tree has 2^k nodes at depth k.

class Node:

    def __init__(self, data):
        # initializes the data members
        self.left = None
        self.right = None
        self.data = data


root = Node(data_root)

def create_complete_tree():
        row = [root]

        for i in range(h):

            newrow = []
            for node in row:
                left = Node(data1)  
                right = Node(data2)  

                node.left = left
                node.right = right

                newrow.append(left)
                newrow.append(right)


            row = copy.deepcopy(newrow)



def traverse_tree(node):
        if node == None:
            return
        else:
            traverse_tree(node.left)
            print node.data
            traverse_tree(node.right)

create_complete_tree()

print 'Node traversal'

traverse_tree(root)

The tree traversal only gives the data of root and its children. What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:27:00+00:00Added an answer on May 14, 2026 at 4:27 am

    The main problem here is that you are using deepcopy on the temporary list. Consider what happens each iteration:

    1. Your initial root gets inspected, and child nodes get created
    2. These child nodes are placed in newrow
    3. Copies of these child nodes are copied into row for the next iteration.

    This means the subsequent iteration will not be mutating the nodes you created (and which root.left and root.right points to), but copies of them, leaving the originals in their current state (with None for .left and .right)

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