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Home/ Questions/Q 7976443
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Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T08:54:37+00:00 2026-06-04T08:54:37+00:00

Here is my code to get a json response string I am getting this

  • 0

Here is my code to get a json response string

I am getting this string by using this method

NSDictionary *selector = [json valueForKey: @"Title"];
NSMutableArray *dictArray = [[NSMutableArray alloc] initWithObjects: selector,nil];
str1=[[dictArray objectAtIndex:i] valueForKey:@"CompanyName"];

To print the “str1”

I am getting

(
    "hello@developer.com"
),
    (
    "hello@developer.com",
    "helloworld@microsoft.com"
),
    (
    "hello@developer.com"
),
    (
    "hello@developer.com"
),
    (
    "hello@developer.com"
),
    (
    "hello@developer.com"
),
    (
    "hello@developer.com"
),
    (
    "hello@developer.com"
)

)

I am trying to store in array by using “,” operator

like this way

NSArray *SplitStringArray = [str1 componentsSeparatedByString:@", "];

but I didn’t split the string into array of elements

Could please any one help me?

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  1. Editorial Team
    Editorial Team
    2026-06-04T08:54:38+00:00Added an answer on June 4, 2026 at 8:54 am
        NSDictionary *selector = [json valueForKey: @"Title"];
    
        NSMutableArray *dictArray = [[NSMutableArray alloc] initWithObjects: selector,nil];
    
        NSMutableArray *str1Array=[[dictArray objectAtIndex:i] valueForKey:@"CompanyName"];
    
    
            //note this line
        NSMutableArray *SplitStringArray =[[NSMutableArray alloc]init];
    
        for (id eachArray in str1Array) {
    
    
            if ([eachArray count]>0) {
    
    
                for (int i = 0; i<[eachArray count]; i++) {
    
                    NSString *emailid=[NSString stringWithFormat:@"%@",[eachArray objectAtIndex:i]];
    
                    [SplitStringArray addObject:emailid];
    
    
                }
    
            }
    
        }
    
        NSLog(@"SplitStringArray : %@",SplitStringArray);
    
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