Question

Here is my code:

var CDs=$(xml).find("CDs");
var NthChild = $(CDs).find("CD:nth-child(index)"); // nth-child 0th element starts at 1

I’m using the find method here; I have to specify the child node name, which is noted as “CD”. Is there are a faster or shorter method, perhaps one that doesn’t need me to specify the name of the child node (i.e. “CD”) to find the nth child node?

Thank you.

UPDATE

I found a format that doesn’t need to specify the child node by name:

var NthChild = $(CDs).children(":nth-child(index)");

Answer 1

$(xml).find("CDs CD").eq(index);

According to jQuery docs

Because :eq() is a jQuery extension and not part of the CSS
specification, queries using :eq() cannot take advantage of the
performance boost provided by the native DOM querySelectorAll()
method. For better performance in modern browsers, use
$(“your-pure-css-selector”).eq(index) instead.