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Home/ Questions/Q 9124021
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T06:28:43+00:00 2026-06-17T06:28:43+00:00

Here is my code want to access child class method of AdapterVer1 getAdaptObj1() (without

  • 0

Here is my code want to access child class method of AdapterVer1 getAdaptObj1() (without type casting) using object reference of AdapterVersion (Parent class)

abstract class AdapterVersion {

public abstract void getMObject();
public abstract void getCObject();

}

public class AdapterVer1 extends AdapterVersion {

@Override
public void getMObject() {
    System.out.println("AdapterVer1 Mont");

}

@Override
public void getCObject() {
    System.out.println("AdapterVer1 Conf");

}

public void getAdaptObj1() {

}

}

public class AdapterFactory {

public static void main(String []a){
    AdapterFactory adapterFactory= new AdapterFactory();
    AdapterVersion adpater = adapterFactory.getMyObject("ver1");
    adpater.getAdaptObj1();  // Unable to do that
            ((AdapterVer1)adpater).getAdaptObj1(); // Working but DONT WANT THIS

}

public AdapterVersion getMyObject(String version){
    if(version.equals("ver1")){
        return new AdapterVer1();
    }else{
        return new AdapterVer2(); // another declared class
    }
}

}
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  1. Editorial Team
    Editorial Team
    2026-06-17T06:28:44+00:00Added an answer on June 17, 2026 at 6:28 am

    You can’t do that. Because at compile time, the compiler checks whether the method you invoked is accessible or visible in the class of the reference you are using or not.

    So, in this case, since the reference is of Parent class, the compiler will look for the method declaration in the Parent class first in order to successfully compile the code.

    Remember: –

    Compiler is worried about the Reference type, and at runtime, the actual object type is considered, to decide which method to actually invoke.

    The only option you have is to typecast, in which case, the compiler now looks into the class in which you typecasted the reference. Other option is, you can declare an abstract method with that name in Parent class, but from your question, it seems like you explicitly haven’t done that.

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