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Home/ Questions/Q 7063075
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:40:14+00:00 2026-05-28T04:40:14+00:00

Here is my controller code and also my View: @using (Html.BeginForm(Create, Product, FormMethod.Post, new

  • 0

Here is my controller code and also my View:

@using (Html.BeginForm("Create", "Product", FormMethod.Post, new { enctype = "multipart/form-data" })) {
    @Html.ValidationSummary()

    <div class="form-field">
        <p>@Html.LabelFor(m => m.Name)</p>
        @Html.EditorFor(m => m.Name)
    </div>

    <div class="form-field">
        <p>@Html.LabelFor(m => m.Description)</p>
        @Html.EditorFor(m => m.Description)
    </div>

    <div class="form-field">
        <p>@Html.LabelFor(m => m.UnitPrice)</p>
        @Html.EditorFor(m => m.UnitPrice)
    </div>

    <div class="form-field">
        <input type="file" name="image1" />
        <input type="file" name="image2" />
        <input type="file" name="image3" />
    </div>

    <div class="form-field">
        <input type="submit" value="Create" />
    </div>
}

And in the Controller. Don’t focus on the content of the action method, just focus on the parameter of type List<HttpPostedFileBase>. Is this the right way of doing things? As it is, images is null upon submission of the form.

[HttpPost]
public ActionResult Create(ProductModel model, List<HttpPostedFileBase> images)
{
    try
    {
        if (ModelState.IsValid)
        {
            var newProduct = Mapper.Map<ProductModel, Product>(model);
            _productRepository.CreateProduct(newProduct);
            _productRepository.SaveChanges();
        }
        return RedirectToAction("Index");
    }
    catch
    {
        return View(model);
    }
}

If you could provide a very simple example that would be fantastic.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:40:15+00:00Added an answer on May 28, 2026 at 4:40 am

    OK, so this is a simple example on how to do it. The end result:

    enter image description here

    The HTML markup is a simple form, with a submit button.

    @using (Html.BeginForm("Create", "Product", FormMethod.Post, new { enctype = "multipart/form-data" })) {
        @Html.ValidationSummary()
    
        <div class="form-field">
            <p>Select pictures:</p>
            <div class="upload-container">
                <div class="upload">
                    <input type="file" name="files" id="file1" /> 
                    <img src="@Url.Content("~/Public/images/delete.png")" alt="Remove picture." />
                </div>
            </div>        
        </div>
    
        <div class="form-field">
            <input type="submit" value="Create" />
        </div>
    }
    

    We also needs some jQuery magic so that every time someone adds an image, we let them also add in more as needed. A user can upload N images.

    <script type="text/javascript">
        $(document).ready(function () {
            var currentImage = 1;
            $("body").on("change", "input[name='files']", function () {
                var pathToRemoveIcon = "@Url.Content("~/Public/images/delete.png")";
                currentImage = currentImage + 1;
                var htmlToAppend = '<div class="upload"><input type="file" name="files" id="file' + currentImage + '" /><img src="' + pathToRemoveIcon + '" alt="Remove picture." /></div>';
                $('.upload-container').append(htmlToAppend);
            }).on("click", ".upload img", function () {
                if ($(this).parent().siblings().length > 0) {
                    $(this).parent().remove();    
                }
            });
        });
    </script>
    

    And finally the controller code:

    [HttpPost]
    public ActionResult Create(IEnumerable<HttpPostedFileBase> files)
    {
        try
        {
            if (ModelState.IsValid)
            {
                //Persist the files uploaded.
            }
            return RedirectToAction("Index");
        }
        catch
        {
            return View(model);
        }
    }
    
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