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Home/ Questions/Q 889017
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:30:00+00:00 2026-05-15T13:30:00+00:00

Here is my HTML: <div id=nav_bar> <div id=nav_image> <img src=navimage.jpg /> </div> </div> and

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Here is my HTML:

<div id="nav_bar">  
<div id="nav_image">  
<img src="navimage.jpg" />  
</div>  
</div>

and my jQuery:

$("#nav_bar").mouseenter(showNav).mouseleave(hideNav);

function showNav(){  
$("#nav_image").stop().fadeIn(250); }

function hideNav(){  
$("#nav_image").stop().fadeOut(2500); }

The problem was that if the mouse re-entered the nav bar (which is larger in area than the nav image inside it) before the 2500ms were up, the animation would stick. I tried to add the stop() function but it either didn’t seem to apply or would freeze up the whole script depending on my timing. I know I must be missing something fundamental…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:30:01+00:00Added an answer on May 15, 2026 at 1:30 pm

    Not sure about anyone else, but I’ve always had better luck just using .animate() in a situation where the effect may need to be stopped and reversed.

    Example: http://jsfiddle.net/F5kGg/1/

    $("#nav_bar").mouseenter(showNav).mouseleave(hideNav);
    
    function showNav(){  
        $("#nav_image").stop().animate({opacity:1},250); }
    
    function hideNav(){  
        $("#nav_image").stop().animate({opacity:0},2500); }​
    

    EDIT: As noted by @Nick Craver .hover() is a convenient alternative to mouseenter and mouseleave, since it accepts two functions representing both events.

    http://api.jquery.com/hover/

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