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Home/ Questions/Q 6534077
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:12:27+00:00 2026-05-25T10:12:27+00:00

Here is my input field.. <input type=file name=upload_file[] value= id= /> $attach = $_FILES[upload_file[]][name];

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Here is my input field..

<input type="file" name="upload_file[]" value="" id=" "/>

$attach = $_FILES["upload_file[]"]["name"];
$sql = "insert into uploadfile(CAT_ID, SUB_CAT_ID, TAG, DESCRIPTION, UF_NAME, UF_NAME1 , GENRE) values('".$category."','".$subcategory."','".$tag."','".$optionaldescription."','".$attach."','".$attach."','".$genre."')";
copy($_FILES['upload_file[]']['tmp_name'], "upload/".$_FILES['upload_file']['name']);
mysql_query($sql);

Warning: copy() [function.copy]: Filename cannot be empty in C:\xampp\htdocs\test\index.php on line 48
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T10:12:28+00:00Added an answer on May 25, 2026 at 10:12 am

    PHP automatically converts HTML form elements that end in [] to arrays, therefore, access the 0nt element of the array:

    $attach = $_FILES["upload_file"][0]["name"];
    $sql = "insert into uploadfile(CAT_ID, SUB_CAT_ID, TAG, DESCRIPTION, UF_NAME, UF_NAME1 , GENRE) values('".$category."','".$subcategory."','".$tag."','".$optionaldescription."','".$attach."','".$attach."','".$genre."')";
    copy($_FILES['upload_file'][0]['tmp_name'], "upload/".$_FILES['upload_file'][0]['name']);
    mysql_query($sql);
    

    In addition, you should be using move_uploaded_file() in place of copy().

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