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Home/ Questions/Q 8492215
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T22:39:13+00:00 2026-06-10T22:39:13+00:00

Here is my Java code: Scanner userInput = new Scanner(System.in); while (true) { //

  • 0

Here is my Java code:

Scanner userInput = new Scanner(System.in);
while (true) { // forever loop
    try {
        System.out.print("Please type a value: "); // asks user for input
        double n = userInput.nextDouble(); // gets user input as a double
        break; // ends if no error
    }
    catch (Throwable t) { // on error
        System.out.println("NaN"); // not a number
    }
}

You can see what this is supposed to do from the comments.

But when I enter in something that’s not a number, this happens:

Please type a value: abc
NaN
Please type a value: NaN
Please type a value: NaN
Please type a value: NaN
Please type a value: NaN
Please type a value: NaN
Please type a value: NaN

and so on until I force stop it.

In Python I would just do this:

while True:
    try:
        n = float(raw_input("Please type a value: "))
        break
    except Exception:
        print "NaN"

How do I do this in Java?
I’ve tried using a do while.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T22:39:15+00:00Added an answer on June 10, 2026 at 10:39 pm
    while (true) { // forever loop
        try {
            scanner userInput = new Scanner(System.in); 
            System.out.print("Please type a value: "); // asks user for input
            double n = userInput.nextDouble(); // gets user input as a double
            break; // ends if no error
        }
        catch (Throwable t) { // on error
            System.out.println("NaN"); // not a number
        }
    }
    

    you should use scanner class inside the while loop then only it will ask next input value if the given input value is wrong.

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