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Home/ Questions/Q 870971
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:34:00+00:00 2026-05-15T10:34:00+00:00

Here is my Javascript: $.post(‘foo.php’, { request: Request }, function(data) { $.each(data.chats, function(i, chat)

  • 0

Here is my Javascript:

$.post('foo.php', { request: Request }, function(data)
{
    $.each(data.chats, function(i, chat)
    { ... });
});

And here is the JSON that, verified by Firebug and everything else, this code is receiving:

{
    "chats": [
        {
            "chat_id": "22",
            "user_status": "Listening",
            "user_ping": "2010-06-22 15:53:57",
            "messages": [
                {
                    "chat_id": "22",
                    "line_id": "5",
                    "message": "Hello",
                    "timestamp": "15:53"
                }
            ]
        }
    ]
}

… so why, when I run this, does it not work, and Firebug throws the error that the “object is undefined”, with a link to “length = object.length” on line 552 of jquery.js, and shows ‘undefined’ when I do a console.log(data.chats)? A console.log(data) shows the full JSON response, but for some reason it doesn’t want to deal with data.chats… I’ve narrowed the error down the ‘$.each’ line.

I’m reasonably sure this is a very simple mistake and I’ll facepalm when someone points it out to me, but at this point I’m completely confused. (and yes, “chats” is supposed to be a JSON array, to handle multiple chats in the future, same with messages.)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:34:01+00:00Added an answer on May 15, 2026 at 10:34 am

    Tell it that you are expecting JSON — by default it will treat the response as html.

    $.post('foo.php', { request: Request }, function(data) 
    { 
        $.each(data.chats, function(i, chat) 
        { ... }); 
    }, 'json');
    
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