Here is my operator definition in my class : T& operator*(){ return this->element_; }

Question

Asked: June 15, 20262026-06-15T12:30:47+00:00 2026-06-15T12:30:47+00:00

Here is my operator definition in my class :

T& operator*(){
        return this->element_; 
}

When I use it like that, it is called :

std::cout << n->operator*() << std::endl;

It doesn’t, if I try :

std::cout << *n << std::endl;

Any Idea ?

Thanks in advance,

Jérémy

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Editorial Team · Answer 1 · 2026-06-15T12:30:48+00:00

Editorial Team

Looks like n is itself a pointer, so you need **n

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