here is my php code
$titikPetaInti = array();
while($row = mysql_fetch_assoc($hasil2))
{
$titikPetaInti[] = $row['koordinat'];
}
$data = "{titikPeta:".json_encode($titikPetaInti)."}";
echo $data;
?>
then here is my android code
xResultTitikPeta is result request to php
jObject = new JSONObject(xResultTitikPeta);
JSONArray myArray1 = (JSONArray) jObject.getJSONArray("titikPeta");
String[]titikPeta = new String[myArray1.length()];
for(int a = 0; a < myArray1.length(); a++)
{
titikPeta[a] = myArray1.getJSONObject(a).toString();
}
teks1 = (TextView) findViewById(R.id.textView1);
teks1.setText(Arrays.toString(titikPeta));
it displaying null at emulator like no value
–EDIT–
i think there something mistake in parsing code, cus when i display the xResultTitikPeta in android, it give me string result
here is result of xResultTitikPeta
{titikPeta:["-8.705378,115.225189","-8.56056700000000,115.42395100000","-8.57659700000000,115.40065300000","-8.55596300000000,115.41085700000","-8.51855200000000,115.491908000000","-8.54743200000000,115.41036800000","-8.56551100000000,115.45173900000","-8.44321000000000,115.616019000000"]}
OK, I’ve found your bug! As well as fixing the
$data = json_encode(array("titikPeta" => $titikPetaInti));issue, the problem is here:The elements of
myArray1are actually of typestringand cause an exception to be thrown, so you need instead:This produces the output of:
As each element in your array is of the form
"-8.705378,115.225189", the JSON parser assumes they are strings. If you change the elements to"-8.705378","115.225189"you can also use:However, the first version will work too.
Note: my personal preference is that I would declare each array element as: