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Home/ Questions/Q 511847
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:15:33+00:00 2026-05-13T07:15:33+00:00

Here is my precode… $keys = array(‘a’, ‘b’, ‘c’, ‘d’); $number = 10; And

  • 0

Here is my precode…

$keys = array('a', 'b', 'c', 'd');
$number = 10;

And here is my code…

eval('$array[\''.implode('\'][\'',$keys).'\'] = $number;');

Using this, I get the following result…

Array (
    [a] => Array
        (
            [b] => Array
                (
                    [c] => Array
                        (
                            [d] => 10
                        )
                )
        )
)

Now, the problem is that this is the exact result I want, but I don’t want to use eval().

As input to my code, I have a list of keys and a number. The number should be set to the value of the keys array being used to generate child-based keys for a certain array $array.

Is there a different way that I can achieve this? I don’t want to overwrite the keys/numbers with new values as the code works – eval() preserves this already, so my new code should do the same.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:15:33+00:00Added an answer on May 13, 2026 at 7:15 am

    Here is a full code example showing how it would work. Whats important is that you use a reference to the array so you can modify it:

    <?php
        $keys = array('a', 'b', 'c', 'd'); 
        $number = 10;
    
        $org_array = array(
            "a" => "string",
            "z" => array( "k" => false)
          );
    
        function write_to_array(&$array, $keys, $number){
          $key = array_shift($keys);
          if(!is_array($array[$key])) $array[$key] = array();
          if(!empty($keys)){
            write_to_array($array[$key], $keys, $number);
          } else {
            $array[$key] = $number;
          }
        }
    
        write_to_array($org_array, $keys, $number);
    
        print_r($org_array);
    ?>
    
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