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Home/ Questions/Q 7033231
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:02:17+00:00 2026-05-28T01:02:17+00:00

Here is my Prent layout (main.xml) <!– ============================================================ –> <!– All Employees are added

  • 0

Here is my Prent layout (main.xml)

<!-- ============================================================ -->
            <!--  All Employees are added here (added and More then one) -->
            <!-- ============================================================ -->
            <LinearLayout 
                xmlns:android="http://schemas.android.com/apk/res/android"
                android:id="@+id/myLayout"
                android:orientation="vertical"
                android:layout_gravity="center_vertical"
                android:layout_width="fill_parent"
                android:layout_height="wrap_content"
                android:background="#00000000">

                <!-- ++++++++ here extra layout is added programmatically -->


            </LinearLayout>

Here is my another layout file that I want as child, say child.xml

    <?xml version="1.0" encoding="utf-8"?>
<LinearLayout         
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/linearLayout2"         
    android:layout_width="fill_parent"         
    android:layout_height="wrap_content"         
    android:layout_alignParentLeft="true"         
    android:layout_alignParentTop="true"         
    android:gravity="center_vertical"         
    android:orientation="horizontal" >          

    <Button             
        android:id="@+id/btn_left"             
        android:layout_width="100dp"             
        android:layout_height="wrap_content" 
        android:singleLine="false"   
        android:maxLines="2"         
        android:text="hello"/>
    <TextView             
        android:id="@+id/list_title"             
        android:layout_width="fill_parent"             
        android:layout_height="wrap_content"             
        android:layout_weight="0.5"             
        android:gravity="center_horizontal"             
        android:text="Photos"             
        android:textAppearance="?android:attr/textAppearanceLarge" />          
    <Button             
        android:id="@+id/btn_right"             
        android:layout_width="100dp"             
        android:layout_height="wrap_content"             
        android:text="Save" />     
</LinearLayout>

Now in my Main activity I am calling the main.xml and based on the for loop condition I want to add the layout of the child.xml and every time I want to set the different value of the TextView of child.xml

So how it is Possible?

I have done like this:

private void doCalculationForMultipleEmployee() {
    singleEmployee.setVisibility(View.GONE);
    for (int i = 0; i<=tempEmployerList.size()-1; i++) {  
        View repeatedLayout = LayoutInflater.from(getApplicationContext()).inflate(R.layout.test);     
        ((TextView)repeatedLayout.findViewById(R.id.list_title)).setText("Employee"+i);     
        // customize repeatedLayout with other data     
        myLinearLayout.addChild(repeatedLayout);
    }
}

But after doing that I got syntax error at .inflate and at .addChild

So where have I gone wrong? Please help me by some code to add it by for loop.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:02:18+00:00Added an answer on May 28, 2026 at 1:02 am

    Just create a loop like below:

        LinearLayout parent=findViewById(R.id.myLayout);
        for(int i=0;i<list.size();i++)
        {
           LinearLayout llItem=(LinearLayout)LayoutInflater.createFromSource(R.layout.child, null);
           TextView txt= (TextView)llItem.findViewById(R.id.title);
           txt.setText(list.get(i));
           parent.add(llItem);
        }
    
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