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Home/ Questions/Q 6372183
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:12:14+00:00 2026-05-25T01:12:14+00:00

Here is my problem: >>> row0 = [0, 0, 0] >>> row1 = [0,

  • 0

Here is my problem:

>>> row0 = [0, 0, 0]
>>> row1 = [0, 0, 0]
>>> field = {'hor' : (row0[0], row1[0])}
>>> field
{'hor': (0, 0)}
>>> row0[0] = 1
>>> field
{'hor': (0, 0)}

What I actually want to have would be:

>>> field
{'hor': (1, 0)}

I understand this behaviour, but how can I hack around it?

The only way I could think of was this:

I could store the ID of the items in the dictionary, like this:

row0 = [0, 0]
row1 = [0, 0]
field = {'hor' : (id(row0[0]), id(row1[0]))}

But the problem here is the access to the variables by the id (I just need read access). I googled a bit, and the only possible solution I found was using globals().items(), like that:

for key, value in globals().items(): print key, value, id(value)

I hope someone has a better solution for my problem. Thanks in advance!

EDIT:

Sorry, the first code example was a bit too simple. My case more looks like the example above.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:12:15+00:00Added an answer on May 25, 2026 at 1:12 am

    As Felix Kling pointed out: You cannot have a reference to primitive values

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