Question

Here is my program.

#include <stdio.h>

void help(const char *argv);

int main(int argc, const char *argv[]) {

    const char *p;
    int x;

    for(x = 0; x < argc; x++) {
        p = argv[x];
        if(*p == '-') {
            p++;
        }
        switch(*p) {    
            case 'h':
                help(*argv);
                return 0;
            break;
        }
    }
    return 0;
}

void help(const char *argv) {
    fprintf(stderr, "Usage %s: [option]\n", argv[0]);
}

The problem is that during compile process I get

warning: format ‘%s’ expects type ‘char *’, but argument 3 has type
‘int’

How to print program name in help function ?

Answer 1

That should be

help(argv); 

and

void help(const char **argv) {
    fprintf(stderr, "Usage %s: [option]\n", argv[0]);
}

Using a char** because you are passing an array of strings (aka pointers to char).