Question

Here is my query :

/path/newdir/newtext.csv 

newtext.csv looks like below :

Record 1

line 1
line 2
Sample Number: 123456789 (line no. 3)
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Time In: 2012-05-29T10:21:06Z (line no. 21)
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Time Out: 2012-05-29T13:07:46Z (line no. 30)

Record 2

line 1
line 2
Sample Number: 363214563 (line no. 3)
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Time In: 2012-05-29T10:21:06Z (line no. 21)
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Time Out: 2012-05-29T13:07:46Z (line no. 30)

Record 3

line 1
line 2
Sample Number: 987654321 (line no. 3)
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Time In: 2012-05-29T10:21:06Z (line no. 21)
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Time Out: 2012-05-29T13:07:46Z (line no. 30)

Assume there are such 100 records in a newtext.csv
So, now i need the parameters of the entered i/p string, which is something below

Example Input Search String :

123456789

Example Output :

Sample Number: 123456789
Time In: 2012-05-29T10:21:06Z
Time Out: 2012-05-29T13:07:46Z

This is what exactly i need. Can you please help me ?

Answer 1

For plain input^* string,

grep -F "InputString" -A27 inputFile.csv | sed -n '1p;19p;$p'

For pattern(Extended-regex)^* string,

grep -E "InputPattern" -A27 inputFile.csv | sed -n '1p;19p;$p'

Script:

user$ cat script.sh

#!/bin/bash 
grep -F "$1" -A27 inputFile.csv | sed -n '1p;19p;$p'

user$ chmod +x script.sh
user$ ./script.sh "inputString"

Edit:

Non-line number based solution,

#!/bin/bash 
grep -F "$1" -A27 inputFile.csv |sed -n "/$1/p;/^Time\s[^:]*:/p"

* The input must be unique to the file.