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Home/ Questions/Q 8088691
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T19:09:52+00:00 2026-06-05T19:09:52+00:00

Here is my situation, I have a string as follows ‘a’:1 ‘b’:2 ‘c’:3 I

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Here is my situation, I have a string as follows

'a':1 'b':2 'c':3

I want to turn this to a dict, so I have two options:

  1. Split the string by ' ' and then by ':' then put the pairs to a dict.

  2. Replace ' ' with ',', append '{', and '}' to string and use eval() to get a dict.

So my question is which one is faster?

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  1. Editorial Team
    Editorial Team
    2026-06-05T19:09:53+00:00Added an answer on June 5, 2026 at 7:09 pm

    I would do it like this:

    import ast
    result = ast.literal_eval(''.join(["{", s.replace(" ", ", "), "}"]))
    

    You can also do this (although the difference may be negligible):

    import ast
    result = ast.literal_eval("{" + s.replace(" ", ", ") + "}")
    

    It’s better to use ast.literal_eval as it’s safer for this purpose than using eval().

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