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Home/ Questions/Q 7436575
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:15:40+00:00 2026-05-29T10:15:40+00:00

Here is my template function template<typename T> std::stringstream logging_expansion ( T const * value

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Here is my template function

template<typename T> std::stringstream logging_expansion ( T const * value ){
    std::stringstream retval;
    retval = retval << *value;
    return retval;
}

Here is how i call it to use it

logging_expansion( "This is the log comes from the convinient function");

But the linker is telling me that it can not reference the function:

Undefined symbols for architecture x86_64:
  "std::basic_stringstream<char, std::char_traits<char>, std::allocator<char> >     logging_expansion<char>(char const*)", referenced from:
  _main in WirelessAutomationDeviceXpcService.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:15:41+00:00Added an answer on May 29, 2026 at 10:15 am

    You need to provide the implementation of template functions in header files or define the specialization in the header.

    I’m assuming you currently have something like:

    //header.h
    template<typename T> std::stringstream logging_expansion ( T const * value );
    
    //implementation.cpp
    #include "header.h"
    
    template<typename T> std::stringstream logging_expansion ( T const * value ){
        std::stringstream retval;
        retval = retval << *value;
        return retval;
    }
    
    //main.cpp
    #include "header.h"
    
    //....
    logging_expansion( "This is the log comes from the convinient function");
    //....
    

    So you need to move the implementation to the header:

    //header.h
    
    template<typename T> std::stringstream logging_expansion ( T const * value ){
        std::stringstream retval;
        retval = retval << *value;
        return retval;
    }
    
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