Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7914829
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 3, 20262026-06-03T14:14:57+00:00 2026-06-03T14:14:57+00:00

Here is my total user without JOIN statement. mysql> SELECT COUNT(*) AS total ->

  • 0

Here is my total user without JOIN statement.

mysql> SELECT COUNT(*) AS total
    -> FROM users;
+--------+
| total  |
+--------+
| 608000 |
+--------+
1 row in set (0.28 sec)

And with LEFT OUTER JOIN

mysql> SELECT COUNT(*) AS total
    -> FROM users
    ->        LEFT OUTER JOIN users_icon
    ->          ON users.uid = users_icon.iconuid
    ->        LEFT OUTER JOIN icon_code
    ->          ON users_icon.icondata = icon_code.iconid;
+--------+
| total  |
+--------+
| 608084 |
+--------+
1 row in set (3.78 sec)

Here I’ve got different total number. With the LEFT OUTER JOIN how do I get the total number is 608000?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-03T14:14:59+00:00Added an answer on June 3, 2026 at 2:14 pm

    Use:

    count(distinct users.id) to get correct count.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am trying to count the total comments posted by single user. Here is
What is the best MySQL command to count the total number of rows in
Here the total height of all <div> 's are 900 pixels, but the jQuery
total nubi here and i'm trying to writ an application that trackes how far
Total noobie question here. I'm just learning Java, and studying passing arguments to functions.
Total noob question, but here. CSS .product__specfield_8_arrow { /*background-image:url(../../upload/orng_bg_arrow.png); background-repeat:no-repeat;*/ background-color:#fc0; width:50px !important; height:33px
I'm a total newb to LINQ. Here is the code I have so far:
Hey! Total CakePHP noob here. Updated at bottom / This is sort of a
I just want to get the total days in a list of dates. Here
For example, here is a string representing an expression: var str = 'total =

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.