Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 752431
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T14:46:50+00:00 2026-05-14T14:46:50+00:00

Here is some code copied from Thinking in C++ Vol1 Chapter 10. #include <iostream>

  • 0

Here is some code copied from Thinking in C++ Vol1 Chapter 10.

   #include <iostream>
   using namespace std;

   int x = 100;

   class WithStatic {
        static int x;
        static int y;
        public:
             void print() const {
             cout << "WithStatic::x = " << x << endl;
             cout << "WithStatic::y = " << y << endl;
           }
  };

what’s the meaning of const for the function print()? Thanks!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T14:46:51+00:00Added an answer on May 14, 2026 at 2:46 pm

    I’ve heard this described previously as “a method that does not logically change the object”. It means that by calling this method the caller can expect the object’s state to remain the same after the method returns. Effectively, the this pointer becomes a constant pointer to a constant instance of that class, so member variables cannot be altered. The exception to this rule is if member variables are declared with mutable. If a class has mutable member variables, these can be modified by both non-const and const methods. Also, non-const methods cannot be called from within a const method.

    Some people use mutable member variables to cache results of timely computations. In theory, the state of the object does not change (i.e. the only effect is that subsequent calls are quicker, but they produce the same results given the same input).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 499k
  • Answers 500k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer This is not pretty but it works: rm -R $(ls… May 16, 2026 at 12:45 pm
  • Editorial Team
    Editorial Team added an answer Yes. Override the base1 and base2 methods in Derived to… May 16, 2026 at 12:45 pm
  • Editorial Team
    Editorial Team added an answer No, you can't. Unfortunately, UIEvent doesn't expose any public way… May 16, 2026 at 12:45 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

While writing some C code, I decided to compile it to assembly and read
Rookie C++ Programmer here again I'm using VC++ VS2008 and making an attempt at
I would like to instantiate an object from its Class object, using the constructor
For some fantastic reason I find myself debugging a problem in a Classic ASP
I'm looking for a way to accelerate a repeatable task when I write code.
I have a custom thread pool class, that creates some threads that each wait
If I have some classes that implement the same interface, so they all contain
I'm attempting to display a modal dialog as a test run before I try
I've got 3 files that relate to this problem. file.h, file.C and user.C. file.h
I have a custom implementation of ClientCredentials in WCF. Two of the base properties

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.