Question

Here is the code:

class thingsToRent
{
    private static HashMap thingsToRent = new HashMap();
    static
    {
        thingsToRent.put("V-1", new String( "Zumba workout video" ) );
        thingsToRent.put("V-2", new String( "Pumping Iron video" ) );    
    }

    public static String get( String serialEntered )
    {

This is where I need to return the rental string such as Zumba workout or Pumping Iron,

What do I say where I have the ?

        return ?;

I have tried return serialEntered but that just gives me the V-1 or V-2 which I

entered into the console using a scanner

    }
}

class Video extends Thing
{
    public Video( String serialEntered )
    {
        super( serialEntered );
    }

    public void getDescription( String serialEntered )
    {
        String theRentalFound = (String)thingsToRent.get( serialEntered );
        if ( theRentalFound == null )
    {
        throw new IllegalArgumentException("Serial Number not found (" + serialEntered + ")");
        }
        else
        {
            System.out.println( "Video: " + theRentalFound );
        }
    }
}

Answer 1

return thingsToRent.get(serialEntered); 

will serve the purpose but you don’t need that because you have already achieved that in your code.