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Home/ Questions/Q 7829601
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Editorial Team
  • 0
Editorial Team
Asked: June 2, 20262026-06-02T10:50:39+00:00 2026-06-02T10:50:39+00:00

Here is the code: function getTime(j){ var stopClock= new Date(); delta[parseInt(j)]=stopClock.getMilliseconds()-start.getMilliseconds(); } //REST OF

  • 0

Here is the code:

function getTime(j){
  var stopClock= new Date();
  delta[parseInt(j)]=stopClock.getMilliseconds()-start.getMilliseconds();
 }

 //REST OF THE CODE!!
function func(){
{
   for (var i = 0; i < 6; i++){
     start = new Date();
     document.write('<img src="'+URL[i]+'" width="1" height="1" alt="" onload="getTime('+i+');"/>');
    }
 }

 //SOME CODE

setTimeout(function() {
   func();
},100);

However I got this error: getTime is not defined

if I declare getTime like this:

 document.getTime= function (j)

There is no error but it never execute that function.

If I remover the setTimeout, it will work with no problem.

Any thoughts?

Thanks,

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T10:50:40+00:00Added an answer on June 2, 2026 at 10:50 am

    You’re destroying the DOM with your document.write call. In some browsers, this also destroys global variables.

    Instead of document.write, try…

    for (var i = 0; i < 6; i++){
    
        var img = document.body.appendChild(document.createElement('img'));
        img.src = URL[i];
        img.width = 1;
        img.height = 1;
        img.onload = makeHandler(i);
    
    }
    

    function makeHandler(i) {
        return function() {
            getTime(i);
        };
    }
    

    Here’s a simple demonstration of the globals being cleared…

    In Firefox, the second alert will be undefined. In Chrome, the global is retained.

    http://jsfiddle.net/Z9NbR/

    window.foo = 'bar';
    
    alert(window.foo); // now we have it
    
    setTimeout(function() {
        document.write('new content');
    
        alert(window.foo); // now we don't
    }, 100);
    
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