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Home/ Questions/Q 7704527
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T23:42:00+00:00 2026-05-31T23:42:00+00:00

Here is the code, I defined two class named Father and Son, and create

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Here is the code, I defined two class named Father and Son, and create them in the main function:

public class Test {
    public static void main(String[] args) {
        Father father = new Son();
    }
}

class Father {
    private String name = "father";
    public Father() {
        who();
        tell(name);
    }
    public void who() {
        System.out.println("this is father");
    }
    public void tell(String name) {
        System.out.println("this is " + name);
    }
}

class Son extends Father {
    private String name = "son";
    public Son() {
        who();
        tell(name);
    }
    public void who() {
        System.out.println("this is son");
    }
    public void tell(String name) {
        System.out.println("this is " + name);
    }
}

and I got the output like this:

this is son
this is father
this is son
this is son

But I can not understand how this happened? Anyone can tell me why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T23:42:02+00:00Added an answer on May 31, 2026 at 11:42 pm
    1. Let’s start with the constructor of Son.

      public Son() {
          super(); // implied
          who();
          tell(name);
      }
      
    2. Father’s constructor is called.

      public Father() {
          who();
          tell(name);
      }
      
    3. Because who() is overridden by Son, the Son‘s version will be called, printing “this is son”.

    4. tell() is also overridden but the value passed in is Father.name, printing “this is father”.

    5. Finally, the who() and tell(name) calls inside Son‘s constructor will be made printing “this is son” and “this is son” respectively.

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