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Home/ Questions/Q 7078179
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T06:30:53+00:00 2026-05-28T06:30:53+00:00

Here is the code I have so far: public static int mode(int[][] arr) {

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Here is the code I have so far:

 public static int mode(int[][] arr) {
      ArrayList<Integer> list = new ArrayList<Integer>();
      int temp = 0;
      for(int i = 0; i < arr.length; i ++) {
          for(int s = 0; s < arr.length; s ++) {
              temp = arr[i][s];

I seem to be stuck at this point on how to get [i][s] into a single dimensional array. When I do a print(temp) all the elements of my 2D array print out one a time in order but cannot figure out how to get them into the 1D array. I am a novice 🙁

How to convert a 2D array into a 1D array?

The current 2D array I am working with is a 3×3. I am trying to find the mathematical mode of all the integers in the 2D array if that background is of any importance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T06:30:54+00:00Added an answer on May 28, 2026 at 6:30 am

    You’ve almost got it right. Just a tiny change:

    public static int mode(int[][] arr) {
        List<Integer> list = new ArrayList<Integer>();
        for (int i = 0; i < arr.length; i++) {
            // tiny change 1: proper dimensions
            for (int j = 0; j < arr[i].length; j++) { 
                // tiny change 2: actually store the values
                list.add(arr[i][j]); 
            }
        }
    
        // now you need to find a mode in the list.
    
        // tiny change 3, if you definitely need an array
        int[] vector = new int[list.size()];
        for (int i = 0; i < vector.length; i++) {
            vector[i] = list.get(i);
        }
    }
    
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