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Home/ Questions/Q 8013397
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T19:37:19+00:00 2026-06-04T19:37:19+00:00

Here is the code that i have been working on. Apparently the #layout call

  • 0

Here is the code that i have been working on. Apparently the #layout call is executed first for some reason and it gives undefined as the value.

$(function() {

    $(".left").load("PartsList.php", function() {
        alert("success");
    });

    $(".right").load("Custom.php", function() {
        alert("success");
    });

    $("#layout").children().on({
        click: function() {
            alert($(this).attr('id'));

        }
    });

});​

Thank you for your time :).

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  1. Editorial Team
    Editorial Team
    2026-06-04T19:37:20+00:00Added an answer on June 4, 2026 at 7:37 pm

    That’s because .load() is called asynchronously.

    You may bind with

    $("#layout").on({
        click: function() {
            alert($(this).attr('id'));
    
        }
    }, '.left,.right');
    

    instead

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