Question

Here is the code:

void option5 (StudentRecord student[], int n)

{
   double gpaThreshold;
   char enteredMajor;
   int i;

   cout << "Enter a GPA threshold: ";
   cin >> gpaThreshold;
   cin.ignore(80, '\n');

   cout << "Enter a Major: ";
   cin >> enteredMajor;
   cin.ignore(80, '\n');

   enteredMajor = toupper(enteredMajor);

   for (i = 0; i < n; i++)
   {
      if (student[i].gpa >= gpaThreshold && student[i].major == enteredMajor)
      {
         if (i % 10 == 0)
         {
            cin.ignore();
         }
         cout << setw(3) << right << i+1 << ". "  
         << setw(20) << left << student[i].lastName 
         << setw(20) << left << student[i].firstName 
         << setw(8) << left << student[i].major 
         << fixed << setprecision(2) << setw(8) << left << student[i].earnedHours 
         << fixed << setprecision(2) << setw(6) << left << student[i].gpa << endl;
      }
   }
}

StudentRecord is a struct, and the only integer on that line is ‘i’, whereas the pointer (I would have to assume) is .major.

I’m wanting to compare an entered major, with the “Major” values in the array.
E.G. I type in Chem
-turns to CHEM
-fetches all students under that major (and threshold of GPA)
-displays the above statement (all students of ‘X’ major)

Any suggestions? Help? Comments? Positive/Negative Feedback?

EDIT: Here is the struct:

struct StudentRecord
{
   char     lastName [16];  // field definitions of the structure
   char     firstName[16];
   char     hometown [16];
   char     major[5];
   int      studentNumber;
   double   balance;
   int      earnedHours;
   double   gpa;
};

Answer 1

Consider this fragment:

student[i].major == enteredMajor

student[i].major is a char[5], which devolves into a char* in this context. This is a pointer type.

enteredMajor is a char. This is an integral type.

You cannot compare these types.

Perhaps you meant to decalre enteredMajor thus:

char enteredMajor[5];

and compare them like this:

strcmp(student[i].major, enteredMajor) == 0