Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7942043
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 3, 20262026-06-03T23:50:53+00:00 2026-06-03T23:50:53+00:00

Here is the code which I am using to pull data from a public

  • 0

Here is the code which I am using to pull data from a public google docs spreadsheet (exported as a CSV).

<?php
// link to Google Docs spreadsheet
$url='https://docs.google.com/spreadsheet/pub?key=xxxx&output=csv';

// open file for reading
if (($handle = fopen($url, "r")) !== FALSE)
{
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE)
    {
        $totalrows = count($data);
        for ($row=0; $row<=$totalrows; $row++)
        {           
            if (strlen($data[$row])>0)
            {

                $firstname = $data[1];
                $surname = $data[1];

                echo $firstname;
                echo $surname;
            }
        }
        echo '<pre>';
        print_r($data);
        echo '</pre>';
    }
    fclose($handle);
}
exit;

?>

The output I am getting is as follows:

MartinMartin

Array
(
    [0] => Firstname
    [1] => Martin
)

CarlinCarlin

Array
(
    [0] => Surname
    [1] => Carlin
)

I am just confused as to what I am doing wrong, I am looking to be able to set the data as variables so that they can be echoed later in the script.

i.e.

<?php echo $firstname; ?> 

Should echo Martin, not MartinMartin.

This is how the data is stored in the spreadsheet:

    A          B
1  Firstname Martin
2  Surname   Carlin

Any help appreciated!

Update

Changed the structure now as follows (sorry for the long-windedness and repetition):

// open file for reading
if (($handle = fopen($url, "r")) !== FALSE)
{
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE)
    {
        for ($row = 0; $row < count($data); $row += 2)
        {
            $firstname = $data[$row][1];
            $surname = $data[$row + 1][1];
        }



    }
    fclose($handle);
}
echo 'Firstname: '.$firstname.'<br /><br />';
echo 'Surname: '.$surname;
exit;
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-03T23:50:55+00:00Added an answer on June 3, 2026 at 11:50 pm

    You are getting MartinMartin because you are setting firstname and surname to the same data[1] value and echoing both out together per row iteration. If you comment out echo $surname, you will find that it does just output Martin. Bear in mind that Martin’s surname Carlin is on a different row to his first name too, so you won’t be able to just do $surname = $data[1] to get it. You would need to look ahead to the next row to get his surname. You’d probably want to iterate the $row array in 2-step fashion so you could index $data[$i][1] and $data[$i + 1][1] for first name and surname.

    $rows = array();
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE)
    {
        $rows[] = $data;
    }
    
    fclose($handle);
    
    for ($i = 1; $i < count($rows); $i += 2) 
    {
        $first = $rows[$i][1];
        $surname = $rows[$i + 1][1];
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Here is my code which is doing the conversion from hex to decimal. The
I am trying to understand this inline assembly code which comes from _hypercall0 here
So I have found this code here This basically lets me pull some data
Here is jquery code which hides my table cells with the ID of .style2:
Here is my code which checks if the file exists : #include<stdio.h> #include<zlib.h> #include<unistd.h>
I have some code here which works perfectly in firefox but not in chrome
I have this piece of Open MP code here which performs an integeration of
I'm just trying out the allegro library, and here is the code which I've
I want to create a dynamic Expression<Func<T,Y>> . Here is the code which works
I have this code here, which is intended to allow any type of arguments:

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.