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Home/ Questions/Q 5963391
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Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T19:14:43+00:00 2026-05-22T19:14:43+00:00

Here is the end of the javascript which runs when the button is clicked

  • 0

Here is the end of the javascript which runs when the button is clicked

xmlObj.open ('GET', /ajax.php, true);
xmlObj.send ('');
}

So this executes the php script ajax.php in the root directory:

<?php
echo "<script type='text/javascript'>\n";
echo "var e = document.getElementById('widget_more_');\n";
echo "e.innerHTML += '<p> <a>TEST</a> </p>';\n";
echo "</script>";
?>

Which is a javascript code that searches the html document for the element by id and appends the TEST link to it. I have ran this javascript in the html normally without trying to echo it through php and it works! BUT not when I try to do it through php! What am I doing wrong?

The reason I am doing it this way is because TEST is actually going to be a string from a php variable.

Please advise me.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T19:14:44+00:00Added an answer on May 22, 2026 at 7:14 pm

    Better would be:

    ajax.php

    <?php
    $string = 'TEST';
    echo $string;
    ?>
    

    JavaScript

    window.onload = function() {
        var e = document.getElementById('widget_more_');
        xmlhttp = window.XMLHttpRequest ? new XMLHttpRequest() : new ActiveXObject('Microsoft.XMLHTTP');
        xmlhttp.open('GET', '/ajax.php', true);
        xmlhttp.onreadystatechange = function() {
            if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
                e.innerHTML += '<p><a>' + xmlhttp.responseText + '</a></p>';
            }
        }
        xmlhttp.send(null);
    }
    

    I don’t really understand why you can’t use a PHP variable.

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