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Home/ Questions/Q 8253673
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T00:57:18+00:00 2026-06-08T00:57:18+00:00

Here is the simplified problem. template <class T> std::string name(const T&); // This is

  • 0

Here is the simplified problem.

template <class T>
std::string name(const T&);  // This is the template 
                             // I want to explicitly specialize.

class Outer
{
    class Inner
    {
    };

    class Container : public ::Container<Inner> // This causes also an implicit
                                                // specialization of f::name
    {
    };
};

How can I specialize

template <class T>
std::string name(const T&);

for Outer::Inner ?

I cannot declare the explicit specialization in three places I considered:

template <class T>
std::string name(const T&); 

// 1. Here I cannot forward declare a nested class

class Outer
{
    class Inner
    {
    };

    // 2. Here I get error: explicit specialization
    //    in non-namespace scope 'class Outer'

    class Container : public ::Container<Inner>
    {
    };
};

// 3. Here I get error: specialization of '...' after instantiation

How can I solve this problem?

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  1. Editorial Team
    Editorial Team
    2026-06-08T00:57:20+00:00Added an answer on June 8, 2026 at 12:57 am

    Have a look at this article. You might be better off just writing a name function for the specific type you want to “specialize” for:

    std::string name(const Outer::Inner&);
    
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