Question

Here is the structure of the content, I want to select all LI except the first two (ie no-link)

jQuery(document).ready(function(){

  var nosubnav = jQuery('.first-level li:not(:has(ul))');
  var nosubnavsize = jQuery('.first-level li:not(:has(ul))').size();
  jQuery(nosubnav).css('border' , '1px solid red');
  alert('List item which does not have submenu  '+nosubnavsize);

});

---

div class="navigation-container">
    <ul class="first-level">
    <li><a href="#">No Link</a></li>
    <li><a href="#">No Link</a></li>
      <li><a href="#">Link 1</a></li>
      <li><a href="#">Link 2</a>
        <ul>
          <li><a href="#">Link2.1</a></li>
          <li><a href="#">Link2.2</a>
            <ul>
                <li><a href="#">Link 2.2.1</a></li>
            </ul>
          </li>
        </ul>
      </li>
      <li><a href="#">Link </a></li>
    </ul>  
  </div>

related Question : How to count li which does not have ul?

Answer 1

$("ul.first-level > li:gt(1)").hide()

I’m assuming you’re talking about the LIs which are on the top level, i.e. direct descendants of .first-level. Otherwise, you can omit the parent child selector (>).

http://api.jquery.com/gt-selector/