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Home/ Questions/Q 982109
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:38:44+00:00 2026-05-16T04:38:44+00:00

Here is this line in perl: open my $fh_echo, ‘-|’ or exec $sshstr \$str\;

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Here is this line in perl:

open my $fh_echo, '-|' or exec "$sshstr \"$str\"";

Basically it exec’s $sshstr and then the output goes into $fh_echo, somehow. I am curious as to the mechanisms that go behind this operation. Can someone explain what the ‘-|’ means?

Also how does this loads the output into $fh_echo? Does it output it little by little or is $fh_echo simply a handle to the output of exec?

Haha I can’t even google this cuz -| don’t show up in the results.

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:38:45+00:00Added an answer on May 16, 2026 at 4:38 am

    See perlfork. That’s a forking pipe open.

    Basically, |- pipes output to a forked child process, and -| reads (within the child process) from the parent.

    From perldoc -f open:

    If you open a pipe on the command ‘-‘, i.e., either ‘|-‘ or ‘-|’ with 2-arguments (or 1-argument) form of open(), then there is an implicit fork done, and the
    return value of open is the pid of the child within the parent process, and 0 within the child process.

    In your example, you’re opening a pipe to read from a child process, then forking, then in the child, replacing the process with $sshstr.

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