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Home/ Questions/Q 6830539
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:37:47+00:00 2026-05-26T22:37:47+00:00

Here is what I’ve copied from MSDN about new operator: The new operator cannot

  • 0

Here is what I’ve copied from MSDN about new operator:

The new operator cannot be used to allocate a function, but it can be
used to allocate pointers to functions. The following example
allocates and then frees an array of seven pointers to functions that
return integers.

int (**p) () = new (int (*[7]) ());
delete *p;

Well there is nothing strange with first line, it allocates an array of pointers to functions, but I just don’t understand how the second deletes that array? I think it should be:

delete[] *p;

Can anyone explain this?

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:37:48+00:00Added an answer on May 26, 2026 at 10:37 pm

    Frankly speaking the right answer was written in the avakar’s comment.
    The right code is

    delete[] p;
    

    delete *p; is incorrect for two reasons:

    1. we must use delete[] for all dynamically allocated arrays. Using
      delete will cause an undefined behaviour.
    2. pointers to static and member functions cannot be deleted
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