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Home/ Questions/Q 8048141
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T06:20:21+00:00 2026-06-05T06:20:21+00:00

Here is working example: http://jsfiddle.net/nnrgu/1/ And here i change to background-position:0px -70px and see

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Here is working example:

http://jsfiddle.net/nnrgu/1/

And here i change to background-position:0px -70px and see what’s happening:

http://jsfiddle.net/nnrgu/2/

linear-gradient, it’s gone!

I’m doing it wrong or it’s supposed to work this way?
How to move linear-gradient with background-image together or keep linear-gradient unmovable?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-05T06:20:23+00:00Added an answer on June 5, 2026 at 6:20 am
    background-position: 0 -70px, 0 0;
    

    does the trick. Since you declare multiple background-images comma-separated, you can declare for each image a single position, also comma-separated.

    http://jsfiddle.net/nnrgu/3/

    I even prefer the shorthand:

    background: <color> image1 position1 repeat1 attachment1, image2 position2 repeat2 attachment2, ... ;
    

    This way it is clear which position/repeat belongs to which image with less characters.

    Sidenote:When you have 0 as value, just omit the unit.

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