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Home/ Questions/Q 8978647
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T19:39:55+00:00 2026-06-15T19:39:55+00:00

Here it’s my code : Write-Host Field 1 : $variable1 Write-Host Field 2 :

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Here it’s my code :

Write-Host "Field 1 : " $variable1  
Write-Host "Field 2 : " $variable2
Write-Host "Field 3 : " $variable3
Write-Host "Field 4 : " $variable4

I get an output like :

   Field 1    : " $variable1    
   Field 2          : " $variable2
   Field 3      : " $variable3
   Field 4           : " $variable4

How can I align them?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T19:39:56+00:00Added an answer on June 15, 2026 at 7:39 pm

    I think, based on his previous questions that field1,2,3 … are db fields names with variable length.

    first solution, not very elegant but you can use the -f format operator to add some extra white-spaces to align your second column (bellow we use 40 characters minus the length of first column)

    $field1=@("name";"username1")
    $field2=@("age";24)
    $field3=@("email";"you@there.com")
    
    wh $field1[0] " : " $field1[1] 
    wh $field2[0] " : " $field2[1]
    wh $field3[0] " : " $field3[1]
    
    wh
    
    #fill some extra whitespaces 
    $spaces1=40 - $field1[0].Length
    $spaces2=40 - $field2[0].Length
    $spaces3=40 - $field3[0].Length
    "{0}{1,$spaces1}" -f $field1[0], " : "+$field1[1]
    "{0}{1,$spaces2}" -f $field2[0], " : "+$field2[1]
    "{0}{1,$spaces3}" -f $field3[0], " : "+$field3[1]
    

    result

    name  :  username1
    age  :  24
    email  :  you@there.com
    
    name                                  : username1
    age                                   : 24
    email                                 : you@there.com
    

    Second solution

    If you create pscustom objects, then you can use all those fancy cmdlets such as format-table 🙂 :

    $col=@(
    [PSCustomObject]@{$field1[0]=$field1[1]},
    [PSCustomObject]@{$field2[0]=$field2[1]},
    [PSCustomObject]@{$field3[0]=$field3[1]}
    )
    
    $col |ft
    

    Result :

    Name                           Value                                                                                 
    ----                           -----                                                                                 
    name                           username1                                                                             
    age                            24                                                                                    
    email                          you@there.com  
    
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