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Home/ Questions/Q 3393982
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T04:06:56+00:00 2026-05-18T04:06:56+00:00

here my code- $things = mysql_real_escape_string(implode(‘,’, $_POST[‘things’]),$link); $q = INSERT INTO tblslider(src) VALUES (‘.$things.’);

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here my code-

$things = mysql_real_escape_string(implode(',', $_POST['things']),$link);

$q = "INSERT INTO tblslider(src) VALUES ('".$things."')";
print_r($q);
$result = $mysqli->query($q) or die(mysqli_error($mysqli));

but my query is getting generated
INSERT INTO tblslider(src) VALUES ('4368122.jpg,5440051.jpg,1047428.jpg') but it should be
INSERT INTO tblslider(src) VALUES ('4368122.jpg'),('5440051.jpg'),('1047428.jpg') thats why it is taking it as one record not three.

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  1. Editorial Team
    Editorial Team
    2026-05-18T04:06:57+00:00Added an answer on May 18, 2026 at 4:06 am

    You could do:

    $things = array_map('mysql_real_escape_string', $_POST['things']);
    $q = "INSERT INTO tblslider(src) VALUES ('". implode("'),('", $things)."')";
    

    It generates (with my test data):

    INSERT INTO tblslider(src) VALUES ('a.jpg'),('b.jpg'),('c.jpg')
    

    I forgot: Only use functions like mysql_real_escape_string on the real data, not the SQL string. In your example you apply the function on the already concatenated data.

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