Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 999551
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T07:22:20+00:00 2026-05-16T07:22:20+00:00

Here the problem: the layer gets sucessfully hidden, but when I click the button

  • 0

Here the problem: the layer gets sucessfully hidden, but when I click the button again, it won’t re-appear. Any ideas?

<head>
    ...
    <script type="text/javascript" 
        src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js">
    </script>

    <script type="text/javascript">
    function action() {
        var status;
        status = 1;

        if( status == 1 ) {
            $("#Layer1").hide( "slow" );
            $("#close").attr( "src", "open.jpg" );
            status = 0;
        } else if( status == 0 ) {
            status = 1;
            $("#Layer1").show( "slow" );
            $("#close").attr( "src", "close.jpg" );
        }
    }
    </script>
    <style type="text/css">
    body {
        background-color: #000000;
    }
    #Layer1 {
        position: absolute;
        width: 200px;
        height: 115px;
        z-index: 1;
        left: 179px;
        top: 3px;
    }
    #Layer2 {
        position: absolute;
        width: 101px;
        height: 80px;
        z-index: 2;
        left: 570px;
        top: 473px; 
    }
    </style>

</head>

<body>
    <div id="Layer1"><img src="body.jpg" width="842" height="554" /></div>
    <div id="Layer2"><img src="close.jpg" id="close" width="63" height="64"     
        OnClick="action()"/></div>
</body>
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T07:22:21+00:00Added an answer on May 16, 2026 at 7:22 am

    Define status outside the action function, otherwise it starts off with 1 every time.

    var status = 1; function action(){}
    

    Provided your logic is right, this should work.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 496k
  • Answers 496k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer You can use patch to apply diffs. Make sure you're… May 16, 2026 at 11:46 am
  • Editorial Team
    Editorial Team added an answer Put all your JS files to use in an array.… May 16, 2026 at 11:46 am
  • Editorial Team
    Editorial Team added an answer You can block access to a site, or portions of… May 16, 2026 at 11:46 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

I have a problem I don't understand regarding UIViews and Core Animation. Here's what
Before any one suggests HTML, I explain later why thats not an option here.
Firstly I tried fiding some similar posts but could not quite find anything. Mainly
I'm using the Spring MVC to build a thin layer on top of a
first post here so sorry for the length of it. I've been lurking and
I have a schema here where I am trying to include/import another schema that
I'm writing a windows application in C++ and encountered the following problem when working
I am trying to parse F# type syntax. I started writing an [F]Parsec grammar
I've been trying to build this small java app. I find it very difficult
When calling an unmanaged Dll from a c# application I get an AccessViolationException .

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.