Question

Here’s a lamba wrapper expression defined:

function <int(double)> f = 
     [](double x) -> int{ return static_cast <int> (x*x); };

It is used like this:

f(someintvalue);

What is the difference between normal functions and wrapped lambdas?

Answer 1

question is – what is the difference between normal function and wrapped lambda?

Normal function is a normal function and what you call “wrapped lambda” is actually a function object.

By the way, why use std::function? You could simply write this:

auto f = [](double x) { return static_cast <int> (x*x); };

//call
int result = f(100.0);

Also, I omitted the return type, as it is implicitly known to the compiler from the return expression. No need to write -> int in the lambda expression.