Question

Here’s a puzzler. I have a variable that contains computer file paths. I need to separate the filename from the path.

Example:
From this:

$filepath = C:\\User\Me\Myfiles\file.jpg

I need this:

$path = C:\\User\Me\Myfiles\
$file = file.jpg

I know how to get the substrings of $filepath using substr. The problem is using “\” as a “needle” to get the position of the filename.

This causes an error:

$pos = strrpos("\",$filepath);

This doesn’t cause an error, but doesn’t give me a value for $pos:

$pos = strrpos("\\",$filepath);

As always, any help with be rewared with my eternal gratitude.

Answer 1

$pos = strrpos("\\",$filepath);

This is trying to find the position of $filepath in the string "\\". Unless the $filepath is a single backslash, no position will be returned.

You want to swap the two arguments around.

$pos = strrpos($filepath, "\\");

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Also, basename($filepath) or pathinfo($filepath, PATHINFO_BASENAME) can be used to get the file name.