Question

Here’s a query:

@projects = @user.projects.includes(:company => :workers)

In my view, I want to order a list of these projects by the tags that belong to the company.

So, projects belonging to the company’s urgent tag come first, then elevated, then all others.

I think one way to do this is to define @companies, then define:

@urgent = @companies.tagged_with('urgent')
@elevated = @companies.tagged_with('elevated')
@others = @companies.tagged_with('urgent', 'elevated', :exclude => true)

# view:
@urgent.each do |u| ... end
@elevated.each do |e| ... end
@others.each do |o| ... end

1. How do I get @companies in the first place?

How can you collect all the companies together when the first query is the one I showed at the top? @companies = @projects.collect{|p| p.company} produces a non-searchable array.

2. Is there a more elegant way of displaying the projects than doing three loops?

Answer 1

I dont think you can do this without using 2 queries.

@projects = @user.projects.includes(:company => :workers)
@companies = Company.find(@projects.collect(&:id))

As for rendering the tags, you could do:

ordered_tags = ['urgent', 'elevated']

ordered_tags.each do |tag|
  @companies.tagged_with(tag).each do |company|
    my_render_logic
  end
end

@companies.tagged_with(*ordered_tags, :exclude => true).each do |company|
  my_render_logic
end