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Home/ Questions/Q 7766955
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T15:33:16+00:00 2026-06-01T15:33:16+00:00

Here’s a sample code: #include <stack> #include <cstddef> template <std::size_t N, template <class> class

  • 0

Here’s a sample code:

#include <stack>
#include <cstddef>

template <std::size_t N,
         template <class> class Stack = std::stack
         >   
class Tower : protected Stack<int>
{   
    public:
        Tower() : Stack<int>(N)
        {   
        }   
};  


int main(int argc, char **argv)
{   
    Tower<5L> tower1();
} 

And I see the compiler (gcc) is not happy:

file.cpp: In function 'int main(int, char**)':
file.cpp:18:11: error: type/value mismatch at argument 2 in template parameter 
list for 'template<long unsigned int N, template<class> class Stack> class Tower'
file.cpp:18:11: error: expected a template of type 'template<class> class Stack',
got 'template<class _Tp, class _Sequence> class std::stack'
file.cpp:18:21: error: invalid type in declaration before ';' token

The standard stack container has this form:

template <class Type, class Container = deque<Type> > class stack;

Meaning I should be fine to pass only one template argument here!

Any thoughts on how to resolve this?
Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-01T15:33:17+00:00Added an answer on June 1, 2026 at 3:33 pm

    'template<class> class Stack',
    got 'template<class _Tp, class _Sequence> class std::stack'
    shows the problem.

    Here is what std::stack looks like

    template<
        class T,
        class Container = std::deque<T>
    > class stack;
    

    As you can see there is a second parameter.

    Adding:

    #include <deque>
    template <std::size_t N,
             template <class T, class = std::deque<T>> class Stack = std::stack
             >   
    

    should make it compile.

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