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Editorial Team
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Asked: 2026-06-15T07:21:39+00:00

Here’s a test procedure from a program I’m working on, I pass in some

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Here’s a test procedure from a program I’m working on, I pass in some parm’s via the stack, one of which is a pointer. When I try to change the value of the dereferenced pointer, the variable isn’t updated. 

_testProc proc
    push bp                             ;Save base pointer to stack
    mov bp, sp                          ;Set new base pointer
    sub sp, 4                           ;Allocate stack space for locals
    pusha                               ;Save registers to stack

    mov di, [bp + 08]                   ;Parm 3 - ptr to variable

    mov word ptr [di], 10   ; <---- Doesn't work. di contains an address, 
                            ;       but what it points at doesn't get updated

    popa                                ;Restore registers from stack
    mov sp, bp                          ;Remove local vars by restoring sp
    pop bp                              ;Restore base pointer from stack
    ret 6                               ;Return and also clean up parms on stack
_testProc endp
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1 Answer

  1. Editorial Team

    The 8086 produces and address by combining the contents of a segment register and an index register; I show that as [SR,IR].

    Your update via register di is updating a location defined by [DS,DI]; mov instructions without any special prefix default to using the DS register. If you got the address DI as an offset for some other segment (ES? SS?) then you are in effect combining the wrong registers to hit the address you desire.

    Your mistake is in not being clear about what the conventions are for passing a “pointer” to your routine. What you’ve define assume a relative offset from DS.

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